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    Plastering & Insulation Formulas
    • 03 Sep 2023
    • 3 Minutes to read
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    Contents

    Plastering & Insulation Formulas

    • Updated on 03 Sep 2023
    • 3 Minutes to read
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    Article summary

    Before reading this article, ensure you have read Measurement - Parts & Labour and Using Formula within Groundplan articles to aid in understanding the following Formula examples.

    Please note:
    • Doubled-sided and single-sided walls would need to be separate Measurements as the Parts and Labour are different.
    • If there is more than one ceiling height on the Project, each height will need to be a separate Measurement with the correct Formula, Parts and Labour applied.

    📝 The Formula values provided in this article are for example purposes only.

    TermExplained
    counttotal counts
    lentotal metres measured
    areatotal square metres measured
    count, len or area / xtotal count/length/area divided by an amount
    count, len or area * xtotal count/length/area multiplied by an amount
    ceil(x)rounding up a decimal value to the next whole number


    Plasterboard

    There are options to produce quantities or lengths of materials depending on what is required and how it is charged.

    Below are three examples:
    1. A per metre rate
    2. The size of sheets required
    3. Requiring 2 sheets to cover 6m length when wall height is 2.4m

    1. Using a per metre rate

    Example Parts using a Length Measurement and assign the cost per metre:

    plastering-metre-rate.png

    PartExplanationFormulaUMO
    Wall lengthHow many total metres measuredceil(len)m
    CorniceHow many total metres measuredceil(len)m
    Insulation (covering 0.58m x 18m)How many rolls are required when the ceiling is 2.4m high divided by the area a roll covers 0.58m x 18m = 10.4m2len*2.4/10.4rolls
    Total wall areaHow many total metres measured multiplied by the ceiling height 2.4len*2.4m2


    2. Using the size of sheets required

    Example Parts for a 6m x 1.2m plasterboard sheet with a wall height of 2.4m Length Measurement:

    plastering-sheet-size.png

    PartExplanationFormulaUMO
    Plasterboard 6m x 1.2mHow many sheets are required when total metres are multiplied by the ceiling is 2.4m high divided by the coverage of a sheet 6m x 1.2m = 7.2m2ceil(len*2.4/7.2)sheets
    CorniceHow many total metres measuredceil(len)m
    Insulation (covering 0.58m x 18m)How many rolls are required when the ceiling is 2.4m high divided by the area a roll covers 0.58m x 18m = 10.4m2len*2.4/10.4rolls
    Total wall areaHow many total metres measured multiplied by the ceiling height 2.4len*2.4m2


    3. Using 2 sheets required to cover 6m length when wall height is 2.4m

    Example Parts for the length of a 6m plasterboard sheet and requiring 2 sheets for a wall height of 2.4m Length Measurement:

    plastering-2-sheets.png

    PartExplanationFormulaUMO
    Plasterboard 6m x 1.2mHow many sheets are required for every 6m multiplied by 2 sheets required for wall height of 2.4mceil(len/6*2)sheets
    CorniceHow many total metres measuredceil(len)m
    Insulation (covering 0.58m x 18m)How many rolls are required when the ceiling is 2.4m high divided by the area a roll covers 0.58m x 18m = 10.4m2ceil(len*2.4/10.4)rolls
    Total wall areaHow many total metres measured multiplied by the ceiling height 2.4len*2.4m2


    Removals

    There are different ways to calculate window and door removals using Parts with negative formula applied. All involve Grouping of Parts. Alternatively, if usage permits, use the Area Cut-Out Tool to remove windows from elevations Plans as well.

    Sliding Door Removal

    Example Parts for the removal of a 2400mm x 2200mm sliding door using a Count Measurement:

    plastering-door-removal-count.png

    PartExplanationFormulaUMO
    Total wall areaCalculating negative m2 of the total area covered by a sliding door 2400mm x 2200mm = 5.28m2 to be removed from the Total wall area Grouped Part-count*5.28m2


    Window Removal

    Example Parts for the removal of any length window with a height of 1.2m using a Length Measurement:

    painting-window-removal-length.png

    PartExplanationFormulaUMO
    Total wall areaCalculating a negative m2 of the total area covered by a window with a height of 1.2m to be removed from the Total wall area Grouped Part-len*1.2m2




    For Formula assistance, please reach out to Support. Go to: Help > Send us a Message.

    Download a PDF copy of Using Formulas within Groundplan here.


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    Attachments
    Labour Conversion Chart 2023(1).pdf
    439.38 KB
    Using Formulas in Groundplan(1).pdf
    4.01 MB
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