- 03 Sep 2023
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# Plastering & Insulation Formulas

- Updated on 03 Sep 2023
- 3 Minutes to read

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Before reading this article, ensure you have read Measurement - Parts & Labour and Using Formula within Groundplan articles to aid in understanding the following Formula examples.

- Doubled-sided and single-sided walls would need to be separate Measurements as the Parts and Labour are different.
- If there is more than one ceiling height on the Project, each height will need to be a separate Measurement with the correct Formula, Parts and Labour applied.

📝 The Formula values provided in this article are for example purposes only.

Term | Explained |
---|---|

`count` | total counts |

`len` | total metres measured |

`area` | total square metres measured |

`count, len or area / x` | total count/length/area divided by an `amount` |

`count, len or area * x` | total count/length/area multiplied by an `amount` |

`ceil(x)` | rounding up a decimal value to the next whole number |

## Plasterboard

There are options to produce quantities or lengths of materials depending on what is required and how it is charged.

Below are three examples:

*1. A per metre rate 2. The size of sheets required 3. Requiring 2 sheets to cover 6m length when wall height is 2.4m*

### 1. Using a per metre rate

Example Parts using a Length Measurement and assign the cost per metre:

Part | Explanation | Formula | UMO |
---|---|---|---|

Wall length | How many measured`total metres` | `ceil(len)` | m |

Cornice | How many measured`total metres` | `ceil(len)` | m |

Insulation (covering 0.58m x 18m) | How many rolls are required when the ceiling is divided by the area a roll covers `2.4m high` `0.58m x 18m = 10.4m2` | `len*2.4/10.4` | rolls |

Total wall area | How many measured multiplied by the ceiling height `total metres` `2.4` | `len*2.4` | m2 |

### 2. Using the size of sheets required

Example Parts for a 6m x 1.2m plasterboard sheet with a wall height of 2.4m Length Measurement:

Part | Explanation | Formula | UMO |
---|---|---|---|

Plasterboard 6m x 1.2m | How many sheets are required when are multiplied by the ceiling is `total metres` divided by the coverage of a sheet `2.4m high` `6m x 1.2m = 7.2m2` | `ceil(len*2.4/7.2)` | sheets |

Cornice | How many measured`total metres` | `ceil(len)` | m |

Insulation (covering 0.58m x 18m) | How many rolls are required when the ceiling is divided by the area a roll covers `2.4m high` `0.58m x 18m = 10.4m2` | `len*2.4/10.4` | rolls |

Total wall area | How many measured multiplied by the ceiling height `total metres` `2.4` | `len*2.4` | m2 |

### 3. Using 2 sheets required to cover 6m length when wall height is 2.4m

Example Parts for the length of a 6m plasterboard sheet and requiring 2 sheets for a wall height of 2.4m Length Measurement:

Part | Explanation | Formula | UMO |
---|---|---|---|

Plasterboard 6m x 1.2m | How many sheets are required for every multiplied by `6m` required for wall height of 2.4m`2 sheets` | `ceil(len/6*2)` | sheets |

Cornice | How many measured`total metres` | `ceil(len)` | m |

Insulation (covering 0.58m x 18m) | How many rolls are required when the ceiling is divided by the area a roll covers `2.4m high` `0.58m x 18m = 10.4m2` | `ceil(len*2.4/10.4)` | rolls |

Total wall area | How many measured multiplied by the ceiling height `total metres` `2.4` | `len*2.4` | m2 |

## Removals

There are different ways to calculate window and door removals using Parts with negative formula applied. All involve Grouping of Parts. Alternatively, if usage permits, use the Area Cut-Out Tool to remove windows from elevations Plans as well.

## Sliding Door Removal

Example Parts for the removal of a 2400mm x 2200mm sliding door using a Count Measurement:

Part | Explanation | Formula | UMO |
---|---|---|---|

Total wall area | Calculating of the total area covered by a sliding door `negative m2` to be removed from the `2400mm x 2200mm = 5.28m2` Total wall area Grouped Part | `-count*5.28` | m2 |

## Window Removal

Example Parts for the removal of any length window with a height of 1.2m using a Length Measurement:

Part | Explanation | Formula | UMO |
---|---|---|---|

Total wall area | Calculating a of the total area covered by a window with a height of `negative m2` to be removed from the `1.2m` Total wall area Grouped Part | `-len*1.2` | m2 |

For Formula assistance, please reach out to Support. Go to: **Help > Send us a Message.**

Download a PDF copy of Using Formulas within Groundplan here.

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