Before reading this article, ensure you have read Adding parts and labour and Using formula within Groundplan articles to aid in understanding the following Formula examples.

📝Note:

Doubled-sided and single-sided walls would need separate measurements as the parts and labour are different.
If there is more than one ceiling height on the project, each height must be a separate measurement with the correct formula, parts and/or labour applied.

Term	Explained
`count`	total counts
`len`	total metres measured
`area`	total square metres measured
`count, len or area / x`	total count/length/area divided by an `amount`
*`count, len or area x`**	total count/length/area multiplied by an `amount`
`ceil(x)`	rounding up a decimal value to the next whole number

Plasterboard

There are options to produce quantities or lengths of materials depending on what is required and how it is charged.

Below are three examples:

A combination of multiple methods may also be used within the same take-off.

1. Using a per metre rate

Example parts using a length measurement and assign the cost per metre:

Part	Explanation	Formula	UoM
Wall length	How many `total metres` measured	`ceil(len)`	m
Cornice	How many `total metres` measured	`ceil(len)`	m
Insulation (covering 0.58m x 18m)	How many rolls are required when the ceiling is `2.4m high` divided by the area a roll covers `0.58m x 18m = 10.4m2`	*`ceil(len2.4/10.4)`**	rolls
Total wall area	How many `total metres` measured multiplied by the ceiling height `2.4`	*`len2.4`**	m2

Example parts for a 6m x 1.2m plasterboard sheet with a wall height of 2.4m Length Measurement:

📝Note: This example uses the height section of the measurement unit.

Part	Explanation	Formula	UoM
Plasterboard 6m x 1.2m	How many sheets are required when `total metres` are multiplied by the ceiling is `2.4m high` automatically applied for the length drawn divided by the coverage of a sheet `6m x 1.2m = 7.2m2`	`ceil(area/7.2)`	sheets
Cornice	How many `total metres` measured	`ceil(len)`	m
Insulation (covering 0.58m x 18m)	How many rolls are required when the ceiling is `2.4m high` automatically applied for the length drawn divided by the area a roll covers `0.58m x 18m = 10.4m2`	`ceil(area/10.4`)	rolls
Total wall area	Total length measured multiplied by the `2.4m high` automatically applied for the length drawn for the total m²	`area`	m²

Example parts for the length of a 6m plasterboard sheet and requiring 2 sheets for a wall height of 2.4m length measurement:

Part	Explanation	Formula	UoM
Plasterboard 6m x 1.2m	How many sheets are required for every `6m` multiplied by `2 sheets` required for wall height of 2.4m	*`ceil(len/62)`**	sheets
Cornice	How many `total metres` measured	`ceil(len)`	m
Insulation (covering 0.58m x 18m)	How many rolls are required when the ceiling is `2.4m high` divided by the area a roll covers `0.58m x 18m = 10.4m2`	*`ceil(len2.4/10.4)`**	rolls
Total wall area	How many `total metres` measured multiplied by the ceiling height `2.4`	*`len2.4`**	m²

There are different ways to calculate window and door removals using parts with negative formula applied. All involve grouping of parts.

Alternatively, if usage permits, use the area cut-out tool to remove windows from elevations plans as well.

Example parts for the removal of a 2400mm x 2200mm sliding door using a count measurement:

Part	Explanation	Formula	UoM
Total wall area	Calculating `negative m2` of the total area covered by a sliding door `2400mm x 2200mm = 5.28m2` to be removed from the total wall area grouped part	*`-count5.28`**	m²

Example parts for the removal of any length window with a height of 1.2m using a length measurement:

📝Note: This example uses the height section of the measurement unit.

Part	Explanation	Formula	UoM
Total wall area	Calculating a `negative m2` of the total area covered by a window with a height of `1.2m` automatically applied for the length drawn to be removed from the total wall area grouped part	`- area`	m²

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